sin^2 x + 3sin x + 2 = 0f for 0 <= x <= 2pi Solve for x Worth 8 marks.

Question

sin^2 x + 3sin x + 2 = 0f for 0 <= x <= 2pi

Solve for x

Worth 8 marks.

in progress 0
Thiên Thanh 4 years 2021-09-04T23:12:45+00:00 1 Answers 11 views 0

Answers ( )

  1. minhkhue
    0
    2021-09-04T23:14:38+00:00
    Reply

    Step-by-step explanation:

    first inequality gives

    (2sinx−1)(sinx+2)>0

    (sinx−

    2

    1

    )>0

    6

    Π

    <x<

    6

    5Π

    second inequality gives

    (x+1)(x−2)<0

    −1<x<2

    common part is

    6

    Π

    <x<2

    hOpe it help!!!

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