Raul empuja su auto de 950 KG sobre una pista rugosa e inclinada 15,0 con una fuerza paralela a la pista, cuya magnitud es de 200 N. Determi

Question

Raul empuja su auto de 950 KG sobre una pista rugosa e inclinada 15,0 con una fuerza paralela a la pista, cuya magnitud es de 200 N. Determina el trabajo mecanico hecho por el peso sobre el auto para un desplazamiento de 5,00m (gravedad=10m/5)

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Calantha 4 years 2021-08-19T09:25:41+00:00 1 Answers 8 views 0

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  1. Dau
    0
    2021-08-19T09:27:31+00:00
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    Answer:

    966 joules

    Step-by-step explanation:

    Step one:

    given data

    mass of car= 950kg

    angle of incline= 15°

    Applied force= 200N

    displacement = 5m

    If we apply a force on an object through a distance work is done, hence Mechanical work is the product of a force applied on an object and its displacement while that force is applied

    Step two:

    Work done= Force * distance

    Since the car is moved on an inclined plane, the expression for the work done is

    Work-done= Frcos∅

    where r is the distance moved

    Work-done= 200*5cos 15

    Work-done= 200*4.83

    Work-done= 966 joules

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