Radioactive radon-222, found in many homes, is a potential health hazard. The half-life of radon-222 is 3.82 days. If you begin with 35.3 mg

Question

Radioactive radon-222, found in many homes, is a potential health hazard. The half-life of radon-222 is 3.82 days. If you begin with 35.3 mg of this isotope, what mass remains after 10.1 days have passed

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Cherry 5 years 2021-07-24T06:33:43+00:00 1 Answers 48 views 0

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    -1
    2021-07-24T06:35:37+00:00

    Answer:

    5.65mg of the isotope remains

    Explanation:

    The radioactive decay follows the equation:

    Ln[A] = -kt + ln[A]₀

    Where [A] is amount of the isotope after time t, k is decay constant, and [A]₀ is initial amount of the isotope.

    k = ln 2 / Half-life

    k = ln 2 / 3.82 days

    k = 0.18145days⁻¹

    Replacing:

    Ln[A] = -0.18145days⁻¹*10.1days + ln[35.3mg]

    ln[A] = 1.7312

    [A] = 5.65mg of the isotope remains

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