Quadrilateral ABCD has vertices A (-1,8), B (2, 12), C (5,8), and D (-1,-2) and its image has a translation (x, y) – (x + 12, y-5). Wha

Question

Quadrilateral ABCD has vertices A (-1,8), B (2, 12), C (5,8), and D (-1,-2)
and its image has a translation (x, y) – (x + 12, y-5). What are the new
coordinates of A’B’C’D’?​

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5 years 2021-08-14T20:33:32+00:00 1 Answers 21 views 0

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    0
    2021-08-14T20:34:34+00:00

    Answer:

    The new coordinates of A’B’C’D’ are A'(x,y) =(11,3), B'(x,y) = (14, 7), C'(x,y) = (17, 3) and D'(x,y) = (11, -7), respectively.

    Step-by-step explanation:

    By using the translation definition, we get the coordinates of the quadrilateral A’B’C’D’:

    A'(x,y) = A(x,y) + T(x,y) (1)

    A'(x,y) = (-1,8) + (12,-5)

    A'(x,y) =(11,3)

    B'(x,y) = B(x,y) + T(x,y) (2)

    B'(x,y) = (2,12) + (12,-5)

    B'(x,y) = (14, 7)

    C'(x,y) = C(x,y) + T(x,y) (3)

    C'(x,y) = (5,8) + (12,-5)

    C'(x,y) = (17, 3)

    D'(x,y) = D(x,y) +T(x,y) (4)

    D'(x,y) = (-1,-2) + (12,-5)

    D'(x,y) = (11, -7)

    The new coordinates of A’B’C’D’ are A'(x,y) =(11,3), B'(x,y) = (14, 7), C'(x,y) = (17, 3) and D'(x,y) = (11, -7), respectively.

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