Q5: An ice skater moving at 12 m/s coasts to a halt in 95m on an ice surface. What is the coefficient of (kinetic) friction betwee

Question

Q5: An ice skater moving at 12 m/s coasts
to a halt in 95m on an ice surface. What is the coefficient
of (kinetic) friction between ice and skates?​

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Khang Minh 5 years 2021-07-30T14:38:08+00:00 1 Answers 85 views 0

Answers ( )

  1. Nho
    0
    2021-07-30T14:39:21+00:00
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    u = 0.077

    Explanation:

    Work done by friction is

    Wf = ∆KE + ∆PE

    -umgx = ∆KE,. ∆PE =0 (level ice surface)

    -umgx = KEf – KEi = -(1/2)mv^2

    Solving for u,

    u = v^2/2gx

    = (12 m/s)^2/2(9.8 m/s^2)(95 m)

    = 0.077

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