PLeaseee ITS Timedddd + BrainlIESTT A 6.50 gram piece of aluminum reacts with an excess of oxygen. use the balanced equation below to

Question

PLeaseee ITS Timedddd + BrainlIESTT
A 6.50 gram piece of aluminum reacts with an excess of oxygen. use the balanced equation below to determine how many grams of aluminum oxide is formed during this reaction.
4 Al + 3 O2 –> 2 Al2O3
a. 662.7 grams of Al2O3
b. 6.1 grams of Al2O3
c. 24.6 grams of Al2O3
d. 12..3 grams of Al2O3

in progress 0
Thành Đạt 4 years 2021-09-03T10:17:19+00:00 1 Answers 145 views 0

Answers ( )

  1. linhdan
    0
    2021-09-03T10:18:41+00:00
    Reply

    Answer:

    d. 12.3 grams of Al2O3

    Explanation:

    Based on the reaction:

    4Al + 3O2 → 2Al2O3

    Where 4 moles of Al reacts in excess of oxygen to produce 2 moles of aluminium oxide.

    To solve this question we must find the moles of Aluminium. With these moles we can find the moles of aluminium oxide using the reaction:

    Moles Al -Molar mass: 26.9815g/mol-

    6.50g * (1mol / 26.9815g) = 0.241 moles Al

    Mass Al₂O₃ -Molar mass: 101.96g/mol-

    0.241 moles Al * (2 mol Al2O3 / 4 mol Al) = 0.120 moles Al2O3

    0.120 moles Al2O3 * (101.96g / mol) =

    12.3g of Al2O3 are produced.

    Right answer is:

    d. 12.3 grams of Al2O3

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )