Phosphorus-33 has a half-life of 25 days. What fraction of the original sample would remain after 300 days?

Question

Phosphorus-33 has a half-life of 25 days. What fraction of the original sample would remain after 300 days?

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Ladonna 4 years 2021-08-21T04:23:41+00:00 1 Answers 33 views 0

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  1. ngochoa
    0
    2021-08-21T04:25:20+00:00
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    Answer:

    The correct answer is – 1/4096.

    Explanation:

    In the starting, there is that the number of atoms is  N
    0
    .

    The number of half-lives in this case, = 300/ 25 = 12

    After the first half-lives or 25 days,  N
    1
    =
    N
    0
    /2

    the half life is that time where half of the sample had decay.

    After the second half-life or 50 days,  N
    2
    =
    N
    1
    /2  =
    N
    0
    /4
    .

    There is division by two the original amount, then after four times you divide four times for  2  that means that you divide by  2
    ^12  =4096
    .

    So the final amount remain is  N
    12
    =
    N
    0
    /4096  or 1/4096.

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