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Phân tích đa thức thành nhân tử : a ( b – c )^3 + b ( c – a )^3 + c ( a – b )^3
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Đáp án:
$(a – b)(b – c)(c -a)(a + b +c)$
Giải thích các bước giải:
$a(b-c)^3 + b(c -a)^3 + c(a -b)^3$
$= a(b^3 – 3b^2c + 3bc^2 – c^3) + b(c^3 – 3c^2a + 3ca^2 – a^3) + c(a^3 – 3a^2b + 3ab^2 – b^3)$
$= ab^3 – ac^3 + bc^3 – ba^3 + ca^3 – cb^3$
$= a^3(c – b) + a(b^3 – c^3) + bc(c^2 – b^2)$
$= (c – b)[a^3 – a(b^2 + bc + c^2) + bc(b + c)]$
$= (c -b)(a^3 – ab^2 – abc – ac^2 + b^2c + bc^2)$
$= (c -b)[b^2(c -a) + bc(c -a) + a(a^2 – c^2)]$
$= (c – b)(c -a)[b^2 + bc – a(a + c)]$
$= (c -b)(c -a)(b^2 – a^2 + bc – ac)$
$= (c -b)(c -a)[(b-a)(b+a) + c(b-a)]$
$= (c -b)(c -a)(b -a)(a + b +c)$
$= (a – b)(b – c)(c -a)(a + b +c)$