One of the first astronauts who traveled to the moon hit a golf ball on the moon. Suppose that the height h in meters of a ball t seconds af

Question

One of the first astronauts who traveled to the moon hit a golf ball on the moon. Suppose that the height h in meters of a ball t seconds after it is hit is described by h = 0.8t2 + 10t. At what times is the ball at a height of 20 meters? The ball is at a height of 20 meters at seconds and at seconds.

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Gerda 5 years 2021-08-25T02:54:17+00:00 1 Answers 16 views 0

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    2021-08-25T02:56:08+00:00

    Answer:v(t) = 24 − 1.6t = 0 ⇒ t =

    24

    1.6

    = 15.

    Step-by-step explanation:

    velocity: v(t) = ds

    dt = 24 − 1.6t (m/s).

    acceleration: a(t) = dv

    dt = −1.6 (m/s2

    ).

    s(15) = 24 · 15 − 0.8(15)2 = 180.

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