On another planet, a marble is released from rest at the top of a high cliff. It falls 4.00 m in the first 1 s of its motion. Through what a

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On another planet, a marble is released from rest at the top of a high cliff. It falls 4.00 m in the first 1 s of its motion. Through what additional distance does it fall in the next 1 s

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Vân Khánh 3 years 2021-08-25T06:09:03+00:00 1 Answers 17 views 0

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  1. thuthuy
    0
    2021-08-25T06:10:11+00:00
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    Answer:

    Distance(h1) = 12 m

    Explanation:

    Given
    :

    Height of cliff (h) = 4m

    Time (t) = 1s

    Intial velocity (u) = 0m/s


    Computation:

    Distance(h) = 1/2(g)(t)²

    4 = 1/2(g)

    g = 8m/s  
    ²

    Distance(h1) = 1/2(g)[(t1)²-(t)²]

    Distance(h1) = 1/2(8)(3)

    Distance(h1) = 12 m

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