Old cannons were built on wheeled carts, both to facilitate moving the cannon and to allow the cannon to recoil when fired. When a 150 kg ca

Question

Old cannons were built on wheeled carts, both to facilitate moving the cannon and to allow the cannon to recoil when fired. When a 150 kg cannon and cart recoils at 1.5 m/s, at what velocity would a 10 kg cannonball leave the cannon?

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Latifah 4 years 2021-08-21T15:01:17+00:00 2 Answers 20 views 0

Answers ( )

  1. Edana
    0
    2021-08-21T15:02:35+00:00
    Reply

    Answer:

    22.5 m/s

    Explanation:

    Applying Newton’s third law of motion

    Momentum of the cannon and cart = momentum of the cannonball

    MV = mv………………… Equation 1

    Where M = mass of the cannon and the cart, V = Recoil velocity of the cannon and the cart, m = mass of the cannonball, v = velocity of the cannonball

    make v the subject of the equation

    v = MV/m…………. Equation 2

    Given: M = 150 kg, V = 1.5 m/s, m = 10 kg

    Substitute into equation 2

    v = 150(1.5)/10

    v = 22.5 m/s

    Hence the cannonball leave the cannon with a velocity of 22.5 m/s

  2. phucdien
    0
    2021-08-21T15:02:48+00:00
    Reply

    Answer:

    v2 = 22.5 m/s

    Explanation:

    Momentum is how hard to stop or turn a moving object . Generally, momentum measures mass in motion. Momentum is a vector quantity. Mathematically,

    p = mass ×  velocity

    The total momentum of an isolated system of  bodies remains constant.

    mometum before = 0

    mass of the canon (m1) = 150 kg

    mass of the ball (m2) = 10 kg

    velocity of the ball (v2) = ?

    velocity of the cannon(v1) = 1.5 m/s

    momentum after = momentum before

    m2v2 + m1v1 = 0

    10v2 = 150 × 1.5

    10v2 = 225

    divide both sides by 10

    v2 = 225/10

    v2 = 22.5 m/s

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