N capacitors are connected in parallel to form a “capacitor circuit”. The capacitance of first capacitor is C, second one is C/2 and third o

Question

N capacitors are connected in parallel to form a “capacitor circuit”. The capacitance of first capacitor is C, second one is C/2 and third one is C/4, forth one is C/8 and so on. Namely, capacitance of a capacitor is one-half of the previous one. What is the equivalent capacitance of this parallel combination when N goes to inifinity?

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Hải Đăng 4 years 2021-08-28T01:01:14+00:00 1 Answers 16 views 0

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  1. diemkieu
    0
    2021-08-28T01:03:09+00:00
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    Answer:

    2C

    Explanation:

    The equivalent capacitance of a parallel combination of capacitors is the sum of their capacitance.

    So, if the capacitance of each capacitor is half the previous one, we have a geometric series with first term = C and rate = 0.5.

    Using the formula for the sum of the infinite terms of a geometric series, we have:

    Sum = First term / (1 – rate)

    Sum = C / (1 – 0.5)

    Sum = C / 0.5 = 2C

    So the equivalent capacitance of this parallel connection is 2C.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )