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Las ruedas de una locomotora de 500 toneladas tiene un coeficiente de friccion estatico con las vias de 0.15 ¿Cual es la fuerza de traccion
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Answers ( )
Answer:
Ff = 7.35*10^5 N
Explanation:
To find the maximum transverse pulling force you use the following formula, for the friction force:
(1)
μ: friction coefficient = 0.15
N: normal force, which is equal to the weight over the wheel
M: mass of th train = 500 ton = 500 000 kg
g: gravitational acceleration = 9.8 m/s^2
You replace the values of the variables in the equation (1):
hence, the maximum transverse pulling force is 7.35*10^5 N