Jet fighter planes are launched from aircraft carriers with the aid of their own engines and a catapult. If in the process of being launched

Question

Jet fighter planes are launched from aircraft carriers with the aid of their own engines and a catapult. If in the process of being launched from rest, the thrust of a jet’s engines is 2.10 105 N and after moving through a distance of 90 m the plane lifts off with a kinetic energy of 5.20 107 J, what is the work done (in J) on the jet by the catapult

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Verity 4 years 2021-08-04T23:16:41+00:00 2 Answers 36 views 0

Answers ( )

  1. Philomena
    0
    2021-08-04T23:18:02+00:00
    Reply

    Answer:

    Work done on jet by catapult; W_cp = 33.1 x 10^(6) J

    Explanation:

    We are given;

    Thrust of the Jets engine; F_thr = 2.1 x 10^(5)N

    Lift off kinetic energy; K_f = 5.20 10^(7) J

    Displacement moved by jet before lift is off; s = 90m

    Now, from the work energy theorem, the net work done on an object is equal to the difference between the initial and final kinetic energy of that object.

    Thus;

    W = KE_f – KE_o

    Where, KE_o is initial kinetic energy and KE_f is final kinetic energy.

    Now, we the net work done on the jet by both the catapult and the Thrust engine is;

    W_n = KE_f = 5.20 10^(7) J

    Now, let’s find the work done by just the Thrust engine.

    The Thrust force is 2.1 x 10^(5)N while the displacement is 90m

    Work done = Force x Distance

    Thus,

    Work done by Thrust engine;

    W_thr = 2.1 x 10^(5) x 90 = 18.9 x 10^(6) J

    Now, net work done on jet by catapult will be;

    W_cp = Wn – W_thr

    Where W_cp is the net work done by catapult

    Wn is total net work done by both catapult and thrust engine

    W_thr is net work done by thrust engine.

    Thus,

    W_cp = 5.20 10^(7) J – 18.9 x 10^(6) J

    W_cp = 33.1 x 10^(6) J

  2. Ladonna
    0
    2021-08-04T23:18:35+00:00
    Reply

    Answer:work done on the jet by the catapult =3.31x107j

    Explanation:

    The kinetic energy of the jet at take off will be equal to the work done by the engines + the work done by the catapult.

    First, the work done by the engines = Force x Distance

    So the work done by the engines (2.10 X 105J)x 90m = 1.89 x 107J

    Having that The total kinetic energy = 5.20x 107J

    The work done on the jet by the catapult = the total kinetic energy – the work done by the engines.

    Therefore the work done on the jet by the catapult = ( 5.20 X 107 J) -(1.89 X 107 )= 3.31x107j

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