In an experiment, a shearwater (a seabird) was taken from its nest, flown a distance 5120 km away, and released. It found its way back to it

Question

In an experiment, a shearwater (a seabird) was taken from its nest, flown a distance 5120 km away, and released. It found its way back to its nest 12.5 days after release. If we place the origin at the nest and extend the + x-axis to the release point, what was the bird’s average velocity in m/s:

a. for the return flight
b. for the whole episode, from leaving the nest to returning

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Lệ Thu 5 years 2021-07-19T07:14:59+00:00 1 Answers 136 views 0

Answers ( )

  1. huyenthanh
    0
    2021-07-19T07:16:47+00:00
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    Answer:

    a)   v = -4.74 m / s, b)  v = 0 m / s

    Explanation:

    Average speed is

              v = Δx /Δt

    a) the variation of the distance on the return trip is

              Δx = -5120 km = -5120 10³ km

    the negative sign is because the bird is going back

              Δt = 12.5 days (24 h / 1 day) (3600 s / 1 h) = 1.08 10⁶ s

              v = -5120 10³ / 1.08 10⁶

              v = -4.74 m / s

    b) the displacement for the round trip is zero, therefore the average velocity is

             v = 0 m / s

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