If you add 25.0 mL of water to 125 mL of a 0.150 M LiOH solution, what will be the molarity of the resulting diluted solution? 0.0450 M LiOH

Question

If you add 25.0 mL of water to 125 mL of a 0.150 M LiOH solution, what will be the molarity of the resulting diluted solution? 0.0450 M LiOH 0.0647 M LiOH 0.125 M LiOH 0.134 M LiOH

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RI SƠ 4 years 2021-07-25T18:10:40+00:00 1 Answers 54 views 0

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  1. niczorrrr
    0
    2021-07-25T18:12:27+00:00
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    Answer:

    solute in a fixed volume of solution

    Concentration(c) = number of moles of solute(n) / volume of solution (v)

    25.0 mL of water is added to 125 mL of a 0.150 M LiOH solution and solution becomes more diluted.

    original solution molarity – 0.150 M

    number of moles of LiOH in 1 L – 0.150 mol

    number of LiOH moles in 0.125 L – 0.150 mol/ L x 0.125 L = 0.01875 mol

    when 25.0 mL is added the number of moles of LiOH will remain constant but volume of the solution increases

    new volume – 125 mL + 25 mL = 150 mL

    therefore new molarity is

    c = 0.01875 mol / 0.150 L = 0.125 M

    answer is 0.125 M

    Explanation:

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