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If the x-component of a vector is 17, and the angle between the vector and the x-axis is 46 degrees, what is the magnitude of the vector? Ro
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Answers ( )
Answer:
24.47
Explanation:
cosθ = adjacent/hypotenuse = x-component/vector magnitude, so cos46° = 17/ vector magnitude. the vector magnitude is, therefore, 24.47
FROM CK-12
Answer:
17.00 N
Explanation:
Given that the x-component of a vector is 17, and the angle between the vector and the x-axis is 46 degrees
The magnitude of the vector will be calculated by first resolving the vector into x component and y component.
X – component
17cos46 = 11.809
Y component
17sin46 = 12.229
We will find the resultant vector by using pythagorean theorem
R = sqrt ( X^2 + Y^2 )
R = sqrt ( 11.809^2 + 12.229^2 )
R = sqrt ( 288.995 )
R = 16.999
R = 17.00 N
Therefore, the magnitude of the vector is 17 .00N