If a mass of 0.55kg attached to a vertical spring stretches the spring 2.0 cm from its original equilibrium, what is the spring constant?

Question

If a mass of 0.55kg attached to a vertical spring stretches the spring 2.0 cm from its original equilibrium, what is the spring constant?

in progress 0
Linh Đan 3 years 2021-09-05T13:52:49+00:00 1 Answers 26 views 0

Answers ( )

  1. thuhuong
    0
    2021-09-05T13:54:39+00:00
    Reply

    Weight G=m×g=0.55×9.8N

    G=k×dx, where dx=2cm is the stretch.

    dx=2cm=0.02m

    m×g=k×dx

    k=m×g/dx=0.55×9.8/0.02=269.5N/m

    Answer: k=269.5N/m

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )