How many solutions does this linear system have? y = 2x – 5 –8x – 4y = –20 one solution: (–2.5, 0) one solution: (2.5, 0) no solution infini

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How many solutions does this linear system have? y = 2x – 5 –8x – 4y = –20 one solution: (–2.5, 0) one solution: (2.5, 0) no solution infinite number of solution

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RI SƠ 4 years 2021-08-16T10:41:52+00:00 1 Answers 47 views 0

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  1. kimchi2
    0
    2021-08-16T10:43:41+00:00
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    Answer:

    one solution: (2.5, 0)

    Step-by-step explanation:

    We are given the following system of equations:

    y = 2x – 5

    -8x – 4y = -20

    Replacing the first equation into the second:

    -8x - 4(2x - 5) = -20

    -8x -8x + 20 = -20

    -16x = -40

    16x = 40

    x = \frac{40}{16}

    x = 2.5

    y

    y = 2x - 5 = 2(2.5) - 5 = 5 - 5 = 0

    Thus the system has one solution: (2.5,0).

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