How many calories are released when 6 grams of 100°C steam turns to 0°C ice?

Question

How many calories are released when 6 grams of 100°C steam turns to 0°C ice?

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RI SƠ 4 years 2021-09-02T18:05:52+00:00 1 Answers 12 views 0

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    2021-09-02T18:07:05+00:00

    Answer: 4276.2 calories

    Explanation:

    Given

    mass of steam is 6 gm at 100^{\circ}C

    Conversion of steam to ice involves

    • steam to water at 100^{\circ}C
    • water at 100^{\circ}C to water at 0^{\circ}C
    • water to the ice at 0^{\circ}C

    Calories released during the conversion of steam to water at 100^{\circ}C

    E_1=mL_v\quad [L_v=\text{latent heat of vaporisation}]\\E_1=6\times 533=3198\ cal.

    Calories released during the conversion of water at 100^{\circ}C to water at 0^{\circ}C

    E_2=mc(\Delta T)\quad [c=\text{specific heat of water,}1\ cal./gm.^{\circ}C]\\E_2=6\times 1\times 100=600\ cal.

    Calories released during the conversion of water to the ice at 0^{\circ}C

    E_3=mL_f\quad [L_f=\text{latent heat of fusion}]\\E_3=6\times 79.7=478.2\ cal.

    The total energy released is

    E=E_1+E_2+E_3\\E=3198+600+478.2=4276.2\ cal.

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