Help!! Marta is solving the equation S = 2πrh + 2πr2 for h. Which should be the result? StartFraction S Over 2 pi r

Question

Help!!

Marta is solving the equation S = 2πrh + 2πr2 for h. Which should be the result?

StartFraction S Over 2 pi r EndFraction equals h. – r = h
StartFraction S minus r Over 2 pi r EndFraction equals h. = h
S – S minus StartFraction r Over 2 pi EndFraction equals h. = h
S – S minus StartFraction 2 pi Over r EndFraction equals h. = h

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RobertKer 4 years 2021-07-23T08:40:12+00:00 2 Answers 884 views 0

Answers ( )

  1. Thunguyet
    1
    2021-07-23T08:41:23+00:00
    Reply

    It is given that,

    → S = 2πrh + 2πr²

    Now subtract 2πr² from the both sides,

    → S – 2πr² = 2πrh + 2πr² – 2πr²

    → S – 2πr² = 2πrh

    Then divide both sides by 2πr,

    → (S-2πr²)/2πr = 2πrh/2πr

    → (S-2πr²)/2πr = h

    Hence, (S-2πr²)/2πr = h is the result.

  2. phucdien
    0
    2021-07-23T08:41:57+00:00
    Reply

    Answer:

    (S-2πr^2)/ 2πr = h

    Step-by-step explanation:

    S = 2πrh + 2πr^2

    Subtract 2 pi r^2 from each side

    S-2πr^2  = 2πrh + 2πr^2 -2πr^2

    S-2πr^2  = 2πrh

    Divide each side by 2 pi r

    (S-2πr^2)/ 2πr = 2πrh/2πr

    (S-2πr^2)/ 2πr = h

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