he plates each have an area of 2 x 10-3 m2, and the spacing between the plates is 6 x 10-3 m. There is no dielectric between the plates. Wha

Question

he plates each have an area of 2 x 10-3 m2, and the spacing between the plates is 6 x 10-3 m. There is no dielectric between the plates. What is the charge on the capacitor

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Ben Gia 4 years 2021-08-21T04:53:27+00:00 1 Answers 13 views 0

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    2021-08-21T04:55:10+00:00

    Complete question:

    The left plate of a parallel plate capacitor carries a positive charge Q, and the right plate carries a negative charge -Q. The magnitude of the electric field between the plates is 100 kV/m. The plates each have an area of 2 x 10⁻³ m², and the spacing between the plates is 6 x 10⁻³ m. There is no dielectric between the plates. What is the charge on the capacitor?

    Answer:

    The charge on the capacitor is 1.77nC

    Explanation:

    Given;

    magnitude of electric field between the plates, E = 100 kV/m

    Area of each plate, A = 2 x 10⁻³ m²

    Distance between the plates, d = 6 x 10⁻³ m

    Charge on the capacitor is calculated as;

    Q = CV

    V = Ed

    C = \epsilon_o \frac{A}{d}

    Q = CV =  \epsilon_o \frac{A}{d}*Ed\\\\ Q =  \epsilon_o AE\\\\Q = 8.85*10^{-12} *2*10^{-3}* 100,000\\\\Q = 1.77 *10^{-9} \ C\\Q = 1.77 \ nC

    Therefore, the charge on the capacitor is 1.77nC

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