Given the function g(x) = 6(4)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3. Part A: Find the average rate of cha

Question

Given the function g(x) = 6(4)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3. Part A: Find the average rate of change of each section. (4 points) Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points) (10 points)

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Hải Đăng 4 years 2021-09-02T18:38:44+00:00 1 Answers 34 views 0

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  1. thaiduong
    0
    2021-09-02T18:40:13+00:00
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    Answer:

    Section A = 18

    Section B = 288

    Section B is 16 times greater than A

    Step-by-step explanation:

    Given the function :

    g(x) = 6(4)^x

    x = 0 to x = 1

    At x = 0

    g(0) = 6(4)^0 = 6(1) = 6

    At x = 1

    g(1) = 6(4)*1 = 24

    Average rate of change for Section A = g(1) – g(0) = 24 – 6 = 18

    Section B ;

    x = 2 ; x = 3

    g(x) = 6(4)^x

    x = 2 to x = 3

    At x = 2

    g(0) = 6(4)^2 = 6 * 16 = 96

    At x = 3

    g(1) = 6(4)^3 = 6(4*4*4) = 384

    Average rate of change for Section B = g(3) – g(2) = 384 – 96 = 288

    Number of times B is greater than A

    Section B / section A = 288 / 18 = 16 times

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