giup minh cau nay voi a: (2 √18 + 3 √8 – 6 √2) : √2

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giup minh cau nay voi a: (2 √18 + 3 √8 – 6 √2) : √2

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Kiệt Gia 4 years 2020-11-24T13:08:26+00:00 2 Answers 70 views 0

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  1. Euphemia
    0
    2020-11-24T13:09:30+00:00
    Reply

    $(2\sqrt[]{18}+3\sqrt[]{8}-6\sqrt[]{2}):\sqrt[]{2}$

    $=(2.\sqrt[]{9.2}+3\sqrt[]{4.2}-6\sqrt[]{2}):\sqrt[]{2}$

    $=(2.3\sqrt[]{2}+3.2\sqrt[]{2}-6\sqrt[]{2}):\sqrt[]{2}$

    $=(6\sqrt[]{2}+6\sqrt[]{2}-6\sqrt[]{2}):\sqrt[]{2}$

    $=6\sqrt[]{2}:\sqrt[]{2}$

    $=6$

  2. Sapo1
    0
    2020-11-24T13:09:39+00:00
    Reply

    a) ($2\sqrt[]{18}+3\sqrt[]{8}-6\sqrt[]{2}$):$\sqrt[]{2}$

    = ($2\sqrt[]{3^2.2}+3\sqrt[]{2^2.2}-6\sqrt[]{2}$):$\sqrt[]{2}$

    = ($2.3\sqrt[]{2}+3.2\sqrt[]{2}-6\sqrt[]{2}$):$\sqrt[]{2}$

    = ($6\sqrt[]{2}+6\sqrt[]{2}-6\sqrt[]{2}$):$\sqrt[]{2}$

    = [$\sqrt[]{2}(6+6-6)$]:$\sqrt[]{2}$

    =$6\sqrt[]{2}$:$\sqrt[]{2}$

    = 6

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