For 2-methylbutane, the AH° of vaporization is 25.22 kJ/mol and the AS° of vaporization is 84.48 J/mol K. At 1.00 atm and 201 K,

Question

For 2-methylbutane, the AH° of vaporization is 25.22 kJ/mol and the

AS° of vaporization is 84.48 J/mol K. At 1.00 atm and 201 K, what is

the AG° of vaporization for 2-methylbutane, in kJ/mol?

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Bơ 5 years 2021-08-16T01:47:21+00:00 1 Answers 93 views 0

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  1. dangkhoa
    0
    2021-08-16T01:49:09+00:00
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    Answer:

    ΔG° = ΔH° – TΔS°

    ΔG° = 25.22-(201 )(0.08448)

    ΔG° = 8.24 kJ/mol

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