find the period of a simple pendulum of 1m length placed on earth and on moon g on moon =1.67m/s² g on earth=10m/s²

Question

find the period of a simple pendulum of 1m length placed on earth and on moon g on moon =1.67m/s² g on earth=10m/s²

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Gia Bảo 4 years 2021-08-27T05:38:58+00:00 1 Answers 9 views 0

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  1. Ladonna
    0
    2021-08-27T05:40:32+00:00
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    Answer:

    T_{m } = 4.86 s

    T_{e} = 1.98 s

    Explanation:

    Given:

    Length = l = 1 m

    Acceleration due to gravity of moon = g_{m} = 1.67 m/s²

    Acceleration due to gravity of Earth = g_{e} = 10 m/s²

    Required:

    Time period = T = ?

    Formula:

    T = 2π \sqrt{\frac{l}{g} }

    Solution:

    For moon

    Putting the givens,

    T = 2(3.14) \sqrt{\frac{1}{1.67} }

    T = 6.3 \sqrt{0.6}

    T = 6.3 × 0.77

    T = 4.86 sec

    For Earth,

    Putting the givens

    T = 2π \sqrt{\frac{1}{10} }

    T = 2(3.14) \sqrt{0.1}

    T = 6.3 × 0.32

    T = 1.98 sec

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