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Find the magnitude of the force F⃗ exerted by the leg on the small pulley. (By Newton’s third law, the small pulley exerts an equal and oppo
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Answers ( )
Explanation:
As the small pulley and mass are not moving, they are stationary.
= mg = (2.27)(9.8)
= 22.246 N
Now resolve the force in the opposite direction.
F = 2Tcos30°
F = (2)(22.246)(cos30°)
F = 38.53 N