f(x)= 10x-5 What is the value of f-1(-4) ?​

Question

f(x)= 10x-5
What is the value of f-1(-4) ?​

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MichaelMet 4 years 2021-08-12T20:28:29+00:00 2 Answers 23 views 0

Answers ( )

    0
    2021-08-12T20:29:35+00:00

    Answer:

    \frac{1}{10}

    Explanation:

    f(x) = y (output)

    y = 10x – 5

    Switch variables.

    Solve for y.

    x = 10y – 5

    x + 5 = 10y

    x/10 + 1/2 = y

    f^{-1}(x) = 1/10x + 1/2

    Put x as -4.

    1/10(-4) + 1/2

    -4/10 + 1/2

    -4/10 + 5/10

    = 1/10

    0
    2021-08-12T20:29:59+00:00

    Answer:

    f^{-1}(-4) = \frac{1}{10}

    Explanation:

    Firstly finding f^{-1}(x)

    So,

    f(x) = 10x-5

    Substitute y = f(x)

    y = 10x-5

    Exchange the values of x and y

    x = 10y-5

    Solving for y

    x = 10y-5

    Adding 5 to both sides

    10y = x+5

    Dividing both sides by 10

    y = \frac{x+5}{10}

    Replace y = f^{-1}(x)

    f^{-1}(x) = \frac{x+5}{10}

    For x = -4

    f^{-1}(-4) = \frac{-4+5}{10}

    f^{-1}(-4) = \frac{1}{10}

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