Each propeller of the twin-screw ship develops a full-speed thrust of F = 285 kN. In maneuvering the ship, one propeller is turning full spe

Question

Each propeller of the twin-screw ship develops a full-speed thrust of F = 285 kN. In maneuvering the ship, one propeller is turning full speed ahead and the other full speed in reverse. What thrust P must each tug exert on the ship to counteract the effect of the ship’s propellers?

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3 years 2021-09-05T14:31:48+00:00 1 Answers 59 views 0

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    2021-09-05T14:33:39+00:00

    Answer:

    tug_tug = 570 10³ l

    Explanation:

    In this problem, each propeller creates a force that makes the boat rotate, so the tugs have to create a die of equal magnitude rep from the opposite direction

               ∑ τ = 0

               F1 la+ (-F1) (-l) = τ-tug

               τ-tug = 2 f1 l

                τ-tug = 2 28510³ l

                tug_tug = 570 10³ l

    where the is the distance from the propane axis to the point where the ship turns

    This force may be less depending on where the tug is.

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