due to smoking a terminally ill patient loses approximately 2% of his lung capacity every 1 month at this rate begining at 100% capacity wha

Question

due to smoking a terminally ill patient loses approximately 2% of his lung capacity every 1 month at this rate begining at 100% capacity what will the patients lung capacity be in one year (12 months) remeber the formula for exponential decay is y=a(1-r)^x
a. 69.4%
b. 76.0%
c. 88.6%
d. 78.5%

in progress 0
Kim Chi 4 years 2021-08-02T17:28:42+00:00 1 Answers 26 views 0

Answers ( )

  1. thugiang
    0
    2021-08-02T17:30:02+00:00
    Reply

    I believe the answer is B.

    Because the patient loses 2% every month. There’s 12 months in a year. 2 x 12 is 24. In a year he loses 24 percent, 100%- 24% = 76%. Which the answer the rest to be 76%

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )