distance moved by the effort in lifting the 5000N load to the height of 15m Question distance moved by the effort in lifting the 5000N load to the height of 15m in progress 0 Physics Thu Thảo 5 years 2021-08-10T07:08:23+00:00 2021-08-10T07:08:23+00:00 1 Answers 10 views 0
Answers ( )
Answer:
Hello There!!
Explanation:
Work done= force × distance moved
Work done=5000N×15m
Work done=75,000J
hope this helps,have a great day!!
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