Consider a particle on which several forces act, one of which is known to be constant in time: Fi = 3.00 i +4.00 ) N. As a result, the parti

Question

Consider a particle on which several forces act, one of which is known to be constant in time: Fi = 3.00 i +4.00 ) N. As a result, the particle moves along a straight path from a Cartesian coordinate of 0.00 m, 0.00 m) to (5.00 m, 6.00 m). What is the work done by Fi?

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Thu Thảo 3 years 2021-08-17T15:02:56+00:00 1 Answers 30 views 0

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  1. bonexptip
    0
    2021-08-17T15:04:17+00:00
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    Given that.

    F=3•i+4•j

    And it from point (0,0)m to (5,6)m

    dx=final position – initial position

    dx=(5,6)-(0,0)

    dx=(5,6)m

    dx=5•i +6•j

    Work done by the force is give by

    W = F•dx

    W=F•dx

    Note that i•i=j•j=1 and i•j=j•i=0

    Then,

    W=(3i+4j)•(5i+6j)

    Therefore,

    W=3i•(5i+6j)+4j•(5i+6j)

    W=15i•i+18i•j+20j•i+24j•j

    W=15+0+0+24

    W=39J

    Then the work done by the force is 39 Joules

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