Chris has a part time job as a cannon ball catcher for the circus. One day he was located an unknown distance away from the cannon. A cannon

Question

Chris has a part time job as a cannon ball catcher for the circus. One day he was located an unknown distance away from the cannon. A cannonball was fired from the cannon at 425 m/s. The speed of sound was 345 m/s. Unfortunately the cannonball went past Chris 0.20 s before he heard the sound of the blast. How far away was the cannon from Chris?

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Tryphena 3 years 2021-09-05T13:11:38+00:00 1 Answers 3 views 0

Answers ( )

  1. Helga
    0
    2021-09-05T13:13:03+00:00
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    Answer: 366.56 meters.

    Explanation:

    Velocity of the cannon ball = 425m/s

    Velocity of sound = 345 m/s

    For the “position” of both, we have the equation:

    Pc = 425m/s*t

    Ps = 345m/s*t

    Where t is time in seconds.

    If the position of Chris is X, we have that if the ball reaches the position of Chris in T seconds, then the soundwave reaches the position of Chris in T + 0.20 seconds, we can write this as:

    425m/s*T = X

    345m/s*(T + 0.20s) = X

    Now we can solve this system of equations. First we can replace the first equation in the second equation and get

    345m/s*(T – 0.20s) = 425m/s*T

    Now we solve this for T.

    345*T + 69 = 425*T

    69 = (425 – 345)*T = 80*T

    T = 69/80 = 0.8625 seconds.

    Now we replace this in the first equation and get:

    X = 425m/s*T = 425m/s*0.8625s =  366.56 meters.

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