Câu 4 nha Question Câu 4 nha in progress 0 Môn Toán Nem 4 years 2020-10-14T08:08:02+00:00 2020-10-14T08:08:02+00:00 1 Answers 132 views 0
Answers ( )
Đáp án:
Ta có :
`3a^2 + 3b^2 = 10ab`
`<=> 3a^2 – 10ab + 3b^2 = 0`
`<=> 3a^2 – 9ab – (ab – 3b^2) = 0`
`<=> 3a(a – 3b) – b(a – 3b) = 0`
`<=> (3a – b)(a – 3b) = 0`
<=> \(\left[ \begin{array}{l}b = 3a\\a = 3b\end{array} \right.\)
TH1 : `b = 3a`
`Q = a^2/b^2 – b^2/a^2`
`= a^2/(3a)^2 – (3a)^2/a^2`
`= a^2/(9a^2) – (9a^2)/a^2`
`= 1/9 – 9`
`= 1/9 – 81/9`
`= -80/9`
TH2 : `a = 3b`
`=> Q = a^2/b^2 – b^2/a^2`
`= (3b)^2/b^2 – b^2/(3b)^2`
`= (9b^2)/b^2 – b^2/(9b^2)`
`= 9 – 1/9`
`= 81/9 – 1/9`
`= 80/9`
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