Calculate the percentage composition of SrBr2

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Calculate the percentage composition of SrBr2

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Thu Thủy 4 years 2021-08-28T23:55:45+00:00 1 Answers 13 views 0

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  1. RuslanHeatt
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    2021-08-28T23:56:47+00:00
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    Answer:

    64.6% of Br and 35.4% of Sr

    Explanation:

    The percentage composition is obtained defining the percentage in mass of each atom in a molecule.

    To solve this question we must find the mass of each atom in 1 mole:

    Molar mass Br: 79.904g/mol

    Molar mass Sr: 87.62g/mol

    The molar mass of SrBr2 is:

    79.904g/mol*2 + 87.62g/mol =

    159.808g/mol + 87.62g/mol =

    247.428g/mol

    The percentage of Br is:

    79.904g/mol*2 = 159.808g/mol / 247.428g/mol * 100

    = 64.6% of Br

    And percentage of Sr is:

    87.62g/mol / 247.428g/mol * 100

    = 35.4% of Sr

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