an object is placed at a distance of 10cm from a convex mirror of focal length 15 cm find the position and nature of the image​

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an object is placed at a distance of 10cm from a convex mirror of focal length 15 cm find the position and nature of the image​

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Nem 4 years 2021-08-03T20:49:07+00:00 1 Answers 10 views 0

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  1. dangkhoa
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    2021-08-03T20:50:20+00:00
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    Answer:

    \boxed{\sf Position \ of \ the \ image = 6 \ cm}

    \boxed{\sf Nature \ of \ the \ image = Virtual \ and \ Erect}

    Given:

    Object distance (u) = -10 cm

    Focal length (f) = 15 cm

    To Find:

    Image distance (v) and nature of the image

    Explanation:

    Mirror Formula:

    \boxed{\bold{\sf \frac{1}{v} + \frac{1}{u} = \frac{1}{f}}}

    Substituting values of u and f in the equation:

    \sf \implies \frac{1}{v} -\frac{1}{10} =\frac{1}{15}

    \sf \implies \frac{1}{v}=\frac{1}{15} +\frac{1}{10}

    \sf \implies \frac{1}{v}=\frac{2}{30}+\frac{3}{30}

    \sf \implies \frac{1}{v}=\frac{2+3}{30}

    \sf \implies \frac{1}{v}=\frac{5}{30}

    \sf \implies v=\frac{30}{5}

    \sf \implies v=6 \ cm

    \therefore

    Image distance (v) = 6 cm

    Nature of the image = Virtual and Erect

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