An industrial flywheel (a solid disk) of mass 10.0 kg and radius 17.3 cm is rotating at an angular speed of 22.0 rad/s. Upon being switched

Question

An industrial flywheel (a solid disk) of mass 10.0 kg and radius 17.3 cm is rotating at an angular speed of 22.0 rad/s. Upon being switched to a slower setting, the flywheel uniformly slows down to 13.5 rad/s after rotating through an angle of 13.8 radians. Calculate the angular acceleration of the flywheel in the process of slowing down

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Hồng Cúc 3 years 2021-08-26T04:40:30+00:00 1 Answers 9 views 0

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  1. thuthuy
    0
    2021-08-26T04:42:26+00:00
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    Answer:

    Explanation:

    During slowing down , initial angular velocity ω₁ = 22 rad /s

    final angular velocity ω₂ = 13.5 rad /s

    using the law’s of motion formula for rotation

    ω₂² =  ω₁² + 2 αθ  , α is angular acceleration and θ is angle in radian rotated during this period

    13.5² = 22² – 2xα x 13.8

    2xα x 13.8 = 484 – 182.25

    α  =  10.93 rad / s²

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