An ice freezer behind a restaurant has a freon leak, releasing 47.97 g of C2H2F3Cl into the air every week. If the leak is not fixed, how ma

Question

An ice freezer behind a restaurant has a freon leak, releasing 47.97 g of C2H2F3Cl into the air every week. If the leak is not fixed, how many kilograms of fluorine will be released into the air over 6 months

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Eirian 4 years 2021-07-13T13:36:01+00:00 1 Answers 21 views 0

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  1. Ben
    0
    2021-07-13T13:37:01+00:00
    Reply

    Answer:

    0.554 kg

    Explanation:

    We want to find the amount of kilograms of fluorine that will be released into the air over 6 months.

    Let’s convert to weeks to get;

    6 × 4 = 24 weeks

    Let’s find Mass leak rate of fluorine from the formula;

    Mass leak rate = (fluorine mass in freon/molar mass of freon) × leak rate

    Molar mass of freon = ((12 × 2) + (1 × 2) + (19 × 3) + (35.5)) = 118.5 g/mol

    Thus;

    Mass leak rate = ((19 × 3)/(118.5)) × 47.97 = 23.074 g/week

    Total fluorine leaked in 6 months = 24 × 23.074 = 553.776 g = 0.554 kg

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