An electric toy with a resistance of 2.50 Ω is operated by a 3.00-V battery. (a) What current does the toy draw? (b) Assuming that the batte

Question

An electric toy with a resistance of 2.50 Ω is operated by a 3.00-V battery. (a) What current does the toy draw? (b) Assuming that the battery delivers a steady current for its lifetime of 4.00 h, how much charge passed through the toy? (c) How much energy was delivered to the toy?

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Nick 4 years 2021-08-21T05:26:34+00:00 1 Answers 28 views 0

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  1. danthu
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    2021-08-21T05:28:13+00:00
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    Answer:

    a) The current is i = 1.2 A

    b) The charge is Q = 17280 C

    c) The energy is E = 43200 J

    Explanation:

    a) The current is given by the ohm’s law wich is:

    i = V/R = 3/2.5 = 1.2 A

    b) Since the charge is steady we can use the following equation to find the charge amount in that time:

    i = Q/t

    Q = t*i

    Where t is in seconds, so we have 4h * 3600 = 14400 s

    Q = 1.2*14400 = 17280 C

    c)  The energy is the power delivered to the toy multiplied by the time:

    P = 1.2*2.5 = 3 W

    E = P*t = 3*14400 = 43200 J

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