An alternative to CFL bulbs and incandescent bulbs are light-emitting diode (LED) bulbs. A 16-W LED bulb can replace a 100-W incandescent bu

Question

An alternative to CFL bulbs and incandescent bulbs are light-emitting diode (LED) bulbs. A 16-W LED bulb can replace a 100-W incandescent bulb or a 24-W CFLbulb.All threebulbsproduce 1600 lumens of light. What is the current through each bulbwhen placed in a circuitwith a 110-Vsource

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Dulcie 5 years 2021-08-22T10:51:20+00:00 1 Answers 12 views 0

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  1. binhan
    0
    2021-08-22T10:53:07+00:00
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    Answer:

    LED bulb = 0.145 A

    Incandescent bulb = 0.909 A

    CFL bulb = 0.218 A

    Explanation:

    Given:

    Power rating of LED bulb (P₁) = 16 W

    Power rating of incandescent bulb (P₂) = 100 W

    Power rating of CFL bulb (P₃) = 24 W

    Terminal voltage across the circuit (V) = 110 V

    We know that, power is related to terminal voltage and current drawn as:

    P=VI

    Express this in terms of ‘I’. This gives,

    I=\frac{P}{V}

    Now, calculate the current drawn in each bulb using their respective values.

    For LED bulb, P_1=16\ W, V=110\ V

    So, current drawn is given as:

    I_1=\frac{16\ W}{110\ V}=0.145\ A

    For incandescent bulb, P_2=100\ W, V=110\ V

    So, current drawn is given as:

    I_2=\frac{100\ W}{110\ V}=0.909\ A

    For CFL bulb, P_3=24\ W, V=110\ V

    So, current drawn is given as:

    I_3=\frac{24\ W}{110\ V}=0.218\ A

    Therefore, the currents drawn through LED bulb, incandescent bulb and CFL bulb are 0.145 A, 0.909 A and 0.218 A respectively.

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