A weather balloon has a volume of 105L at 0.97 atm when the temperature is 318K. What is the volume at 293K and 1.05 atm?

Question

A weather balloon has a volume of 105L at 0.97 atm when the temperature is 318K. What is the volume
at 293K and 1.05 atm?

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Tryphena 4 years 2021-08-13T12:03:45+00:00 1 Answers 134 views 0

Answers ( )

  1. Helga
    0
    2021-08-13T12:05:32+00:00
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    Answer:

    89 L

    Explanation:

    Step 1: Given data

    • Initial pressure (P₁): 0.97 atm
    • Initial volume (V₁): 105 L
    • Initial temperature (T₁): 318 K
    • Final pressure (P₂): 1.05 atm
    • Final volume (V₂): ?
    • Final temperature (T₂): 293 K

    Step 2: Calculate the final volume of the weather balloon

    If we assume that the gas inside the balloon behaves as an ideal gas, we can calculate the final volume of the gas using the combined gas law.

    P₁ × V₁ / T₁ = P₂ × V₂ / T₂

    V₂ = P₁ × V₁ × T₂ / T₁ × P₂

    V₂ = 0.97 atm × 105 L × 293 K / 318 K × 1.05 atm = 89 L

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