a water bomber flying with a horizontal speed of 85m/s at a height of 3000m drops a load on a fire below. How far in front of the target fir

Question

a water bomber flying with a horizontal speed of 85m/s at a height of 3000m drops a load on a fire below. How far in front of the target fire should the load be released?

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Doris 3 years 2021-08-31T00:13:58+00:00 1 Answers 51 views 1

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  1. Vodka
    0
    2021-08-31T00:15:13+00:00
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    Answer:

    2081.65 m

    Explanation:

    We’ll begin by calculating the time taken for the load to get to the target. This can be obtained as follow:

    Height (h) = 3000 m

    Acceleration due to gravity (g) = 10 m/s²

    Time (t) =?

    h = ½gt²

    3000 = ½ × 10 × t²

    3000 = 5 × t²

    Divide both side by 5

    t² = 3000 / 5

    t² = 600

    Take the square root of both side

    t = √600

    t = 24.49 s

    Finally, we shall determine the distance from the target at which the load should be released. This can be obtained as follow:

    Horizontal velocity (u) = 85 m/s

    Time (t) = 24.49 s

    Horizontal distance (s) =?

    s = ut

    s = 85 × 24.49

    s = 2081.65 m

    Thus, the load should be released from 2081.65 m.

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