A tightly wound 1000-turn toroid has an inner radius 1.00 cm and an outer radius 2.00 cm, and carries a current of 1.50 A. The toroid is cen

Question

A tightly wound 1000-turn toroid has an inner radius 1.00 cm and an outer radius 2.00 cm, and carries a current of 1.50 A. The toroid is centered at the origin with the centers of the individual turns in the z = 0 plane. Determine the magnitude field at a distance of 1,10 cm from the origin.

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Edana Edana 3 years 2021-08-11T20:03:39+00:00 1 Answers 34 views 0

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  1. danthu
    0
    2021-08-11T20:04:39+00:00
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    Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT

    Explanation:

    Given;

    Number of turns, N = 1000

    Inner radius, r₁ = 1cm

    Outer radius, r₂ = 2cm

    Current, I = 1.5A

    Magnetic field strength, B = ?

    The magnetic field inside a tightly wound toroid is given by B = μ₀ NI / 2πr

    where,

    a < r < b and a and b are the inner and outer radii of the toroid.

    The magnetic field of toroid is

    B = \frac{u_oNI}{2\pi r}

    Substituting the values in the formula:

    B (1.10cm) = \frac{(4\pi X 10^-^7 ) ( 1000)(1.5)}{2\pi (1.10) } \\\\

    B (1.10cm) = 27.3mT

    Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT

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