A speed skater moving to the left across frictionless ice at 8.6 m/s hits a 4.7-m-wide patch of rough ice. She slows steadily, then continue

Question

A speed skater moving to the left across frictionless ice at 8.6 m/s hits a 4.7-m-wide patch of rough ice. She slows steadily, then continues on at 5.3 m/s.
What is her acceleration on the rough ice?

in progress 0
MichaelMet 4 years 2021-08-19T00:34:28+00:00 1 Answers 25 views 0

Answers ( )

  1. Neala
    0
    2021-08-19T00:36:11+00:00
    Reply

    Answer:

     a = 4.88 m / s²

    Explanation:

    We can solve this exercise using the expressions of kinematics in one dimension

             v² = v₀² – 2a x

    where v is the velocity, v₀ is the initial velocity, at acceleration and ax is the distance, the negative sign is because the velocity decreases because

              a = (v₀² – v²) / 2x

    let’s calculate

             a = (8.6² – 5.3²) / (2   4.7)

             a = 4.88 m / s²

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )