A small circular hole 6.00 mm in diameter is cut in the side of a large water tank. The top of the tank is open to the air. The water is esc

Question

A small circular hole 6.00 mm in diameter is cut in the side of a large water tank. The top of the tank is open to the air. The water is escaping from the hole at a speed of 10 m/s. How far below the water surface is the hole

in progress 0
Farah 4 years 2021-08-21T00:03:03+00:00 1 Answers 201 views 0

Answers ( )

  1. Adela
    0
    2021-08-21T00:05:00+00:00
    Reply

    Answer:

    5.097 m

    Explanation:

    This involves Bernoulli’s equation, so we will use;

    P + ρgh + ½ρv² = constant

    Applying this equation to both points, we have;

    P_i + ρ_water*g*h_i + ½*ρ_water*v_i² = P_f + ρ_water*g*h_f + ½*ρ_water*v_f²

    Since open to air, P_i and P_f will cancel out.

    Also, v_i = 0 and h_f = 0

    ρ_water = 1 g/ml

    v_f is given as 10 m/s

    h_i is depth of the hole below the water surface.

    Thus, plugging in values, we have;

    1*9.81*h_i + 0 = 0 + ½*1*10²

    9.81h_i = 50

    h_i = 50/9.81

    h_i = 5.097 m

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )