A sample of gas contains 0.1700 mol of OF2(g) and 0.1700 mol of H2O(g) and occupies a volume of 19.5 L. The following reaction takes place:

Question

A sample of gas contains 0.1700 mol of OF2(g) and 0.1700 mol of H2O(g) and occupies a volume of 19.5 L. The following reaction takes place: OF2(g) + H2O(g)O2(g) + 2HF(g) Calculate the volume of the sample after the reaction takes place, assuming that the temperature and the pressure remain constant. L

in progress 0
Hồng Cúc 4 years 2021-08-24T16:41:18+00:00 1 Answers 23 views 0

Answers ( )

  1. Bo
    0
    2021-08-24T16:42:31+00:00
    Reply

    Answer: The volume of the sample after the reaction takes place is 29.25 L.

    Explanation:

    The given reaction equation is as follows.

    OF_{2}(g) + H_{2}O(g) \rightarrow O_{2}(g) + 2HF(g)

    So, moles of product formed are calculated as follows.

    \frac{3}{2} \times 0.17 mol \\= 0.255 mol

    Hence, the given data is as follows.

    n_{1} = 0.17 mol,      n_{2} = 0.255 mol

    V_{1} = 19.5 L,         V_{2} = ?

    As the temperature and pressure are constant. Hence, formula used to calculate the volume of sample after the reaction is as follows.

    \frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}

    Substitute the values into above formula as follows.

    \frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{19.5 L}{0.17 mol} = \frac{V_{2}}{0.255 mol}\\V_{2} = \frac{19.5 L \times 0.255 mol}{0.17 mol}\\= \frac{4.9725}{0.17} L\\= 29.25 L

    Thus, we can conclude that the volume of the sample after the reaction takes place is 29.25 L.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )