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A metal sphere A of radius a is charged to potential V. What will be its potential if it is enclosed by a spherical conducting shell B of ra
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Answer:
The potential will be Va/b
Explanation:
So Let sphere A charged Q to potential V.
so, V= KQ/a. ….(1
Thus, spherical shell B is connected to the sphere A by a wire, so all charge always reside on the outer surface.
therefore, potential will be ,
V ′ = KQ/b = Va/b… That is from …..(1), KQ=Va]