A light beam is traveling through an unknown substance. When it strikes a boundary between that substance and the air (nair≈1), the angle of

Question

A light beam is traveling through an unknown substance. When it strikes a boundary between that substance and the air (nair≈1), the angle of reflection is 29.0∘ and the angle of refraction is 39.0∘. What is the index of refraction n of the substance?

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Tryphena 3 years 2021-08-09T14:54:56+00:00 1 Answers 26 views 0

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  1. Gerda
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    2021-08-09T14:56:05+00:00
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    Answer:

    0.7707

    Explanation:

    From Snell’s law,

    n(1) * sin θ1 = n(2) * sinθ2

    Where n(1) = refractive index of air = 1.0003

    θ1 = angle of incidence

    n(2) = refractive index of second substance

    θ2 = angle of refraction

    The angle of reflection through the unknown substance is the same as the angle of incidence of air. Thus this means that θ1 = 29°

    => 1.0003 * sin29 = n(2) * sin39

    n(2) = (1.0003 * sin29) / sin39

    n(2) = 0.7707

    Explanation:

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