A= $\frac{\sqrt{x} - 1}{\sqrt{x} + 1}$ .cho x hãy tính A iii,x= $\sqrt[3]{10 + 6 \sqrt{3}}$ + $\sqrt[3]{10 - 6 \sqrt{3}}$ iv,x= $\frac{1}{1 + \sqrt{3}}$

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A= $\frac{\sqrt{x} - 1}{\sqrt{x} + 1}$ .cho x hãy tính A iii,x= $\sqrt[3]{10 + 6 \sqrt{3}}$ + $\sqrt[3]{10 - 6 \sqrt{3}}$ iv,x= $\frac{1}{1 + \sqrt{3}}$

Question

A= $\frac{\sqrt{x} - 1}{\sqrt{x} + 1}$ .cho x hãy tính A
iii,x= $\sqrt[3]{10 + 6 \sqrt{3}}$ + $\sqrt[3]{10 - 6 \sqrt{3}}$
iv,x= $\frac{1}{1 + \sqrt{3}}$ + $\frac{1}{\sqrt{3} + \sqrt{5}}$ +….+ $\frac{1}{\sqrt{79} + \sqrt{81}}$

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Môn Toán Dulcie 4 years 2020-11-03T02:15:45+00:00 2020-11-03T02:15:45+00:00 1 Answers 89 views 0

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Acacia · Answer 1 · 2020-11-03T02:17:35+00:00

Acacia

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2020-11-03T02:17:35+00:00 November 3, 2020 at 2:17 am

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Đáp án:

Giải thích các bước giải:

CHÚC BẠN HỌC TỐT

$a-frac-sqrt-1-sqrt-1-cho-hay-tinh-a-iii-sqrt-3-10-6-sqrt-3-sqrt-3-10-6-sqrt-3-iv-frac-1-1-sqrt-3$

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