A fast ball thrown with a velocity of 40 m/s (approximately 90 MPH) is struck by a baseball bat, and a line drive comes back toward the pitc

Question

A fast ball thrown with a velocity of 40 m/s (approximately 90 MPH) is struck by a baseball bat, and a line drive comes back toward the pitcher with a velocity of 60 m/s. The ball is in contact with the bat for a time of just 0.04 s. The baseball has a mass of 120 g (0.120 kg). What is the change in momentum of the baseball during this process

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Nick 4 years 2021-09-05T11:46:40+00:00 1 Answers 29 views 0

Answers ( )

  1. thnahdat
    0
    2021-09-05T11:48:27+00:00
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    Answer: 12 kg•m/s

    Explanation:

    Let “toward the pitcher” be the positive direction

    Δp = mΔv = m(vf – vi)

    Δp = 0.120(60 – (-40)) = 12 kg•m/s

    Not asked for, but the average force during impact is

    Δp = FΔt   (Here the units are N•s which are identical to kg•m/s)

    F = 12/0.04 = 300 N

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